﻿ 7343073 Essay

# 7343073

Scholar’s Name Particular date of Experiment- 11/27/12 Particular date Report Posted 11/27/12 Title: Caloric Content of Foodstuff Purpose: to be able to measure the energy content of foods Process: We are going to consider food items and burn them to heat water to determine how much “energy” a food resource can give off. Data Dining tables: Data Stand 1: Meal , Findings | |Food Item Information: |Marshmallow |Peanut / Walnut |Potato Processor chip | |Mass of meals & holder – primary |40. 2g |18.

0g |15g | |Mass of food & holder – final |38. 6g |16. 0g |12. g | |Mass of food burnt |1. 6g |2g |2. 5g | |Mass of beaker |66. 5g |66. 4g |66. 5g | |Mass of beaker & water |107. 2g |108. 2g |108. 2g | |Mass of water |40. 7g |41. g |41. 7g | |Water temp. – initial |23 C |22 C |22 C | |Water temp. – final |31 C |72 C |32 C | |Delta To (oC change) |8 C |50 C |10 C | Findings: The observations are mentioned above.

Identified it really interesting that the peanut was able to develop enough temperature to change the temperature of the water so much. Inquiries: A. Which of the food tested provides the most energy per gram? The spud chip B. How do the experimental benefits compare to printed values? I would personally say that my personal results were normal C. What type of reaction can be used in calorimetry? Combustion reaction D. Exactly what are the products from the reactions? Carbon dioxide and water E. In which did these products go? They will vaporized in the air N.

A student doing an experiment to determine the caloric content of your cashew nut collected this data:? Mass of cashew nut prior to burning: 0. 55 g? After burning: 0. 05 g? Temperature. increase of 200 g of drinking water: 7. 0 oC 1 ) Calculate the entire energy introduced by the burning of the cashew nut by using the water temp. increase, the mass of the water and specific warmth capacity of water. q=delta t by m back button cp , 58576 joules 2 . Determine the energy released per gram of cashew nut consumed in the response. 58, 576j/0. 55g= 106502/4. 184= 24, 455 or perhaps 2 . cal 3. Using the following specifications (carbohydrates (4 Cal/g), proteins (4 Cal/g), and body fat 9 Cal/g), determine the caloric content material of a bag of your favourite snack food. Soup cheese fritos Carbs=60 Protein= 8 Fats= 90 Conclusions: Remember: Lab notes are evidence of your job and of your understanding of the principles demonstrated in the experiments. Also, they are the primary basis for your biochemistry and biology lab grade. Write nicely and try to exhibit your thoughts evidently, concisely, and completely so that someone else may duplicate the results.

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