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COMPONENT I. SPECULATION TESTING PROBLEM 1 A specific brand of neon light conduit was marketed as having an effective life time before burning up out of 4000 hours. A randomly sample of 84 bulbs was tired with a suggest illumination life of 1870 hours and with a sample standard change of 90 hours.

Build a 96 confidence time period based on this sample and stay sure to translate this interval. Answer As population regular deviation is usually unknown, big t distribution can be utilized construct the confidence time period.? The 95% confidence interval is given by? X? capital t? / two, n? 1? S S?, X? /2, n? one particular? n and? Details Confidence Interval Estimation for the Mean Info Sample Standard Deviation Test Mean Test Size Level of confidence 90 1870 84 95% Intermediate Computations Standard Mistake of the Imply 9. 819805061 Degrees of Flexibility 83 t Value 1 . 988959743 Span Half Thickness 19. 53119695 Confidence Period Interval Lower Limit 1850. 47 Span Upper Limit 1889. 53 2 PROBLEM 2 Offered the following data from two independent info sets, perform a one -tail hypothesis test to determine if the means are statistically the same using alpha=0. 05. Will not do a assurance interval. one particular = 35 n2 = 30 xbar1= 32 xbar2 = twenty-five s1=7 s2 = six Answer H0: 1=2 H1: 1&gt, 2 Test figures used is definitely t? X1? X two S a couple of (n1? 1) S12? (n2? 1) S2 n1n2 ~ tn1? n1? 2 where S? n1? n2? two n1? n2 Decision secret: Reject the null hypothesis, if the calculated value of test statistic is more than the critical value. Particulars t Test for Variations in Two Means Data Hypothesized Difference Standard of Significance Inhabitants 1 Sample Sample Size Sample Imply Sample Regular Deviation Human population 2 Test Sample Size Sample Imply Sample Normal Deviation zero 0. 05 35 thirty-two 7 31 25 6th

Intermediate Computations Population you Sample Degrees of Freedom 34 Population a couple of Sample Degrees of Freedom twenty nine Total Examples of Freedom 63 Pooled Difference 43. 01587 Difference in Sample Means 7 big t Test Figure 4. 289648 Upper-Tail Test out Upper Critical Value p-Value Reject the null hypothesis 1 . 669402 3. 14E-05 Conclusion: Decline the null hypothesis. The sample provides enough proof to support the claim that means are different. 3 TROUBLE 3. A test was conducted to ascertain whether sexuality of a screen model af fected the chance that consumers would prefer a brand new product.

A survey of consumers at a trade display which applied a female agent determined that 120 of 300 consumers preferred the merchandise while ninety two of 280 customers preferred the product mainly because it was demonstrated by a girl spokesperson. Do the samples provide sufficient facts to indicate the gender with the salesperson affect the likelihood of the item being positively regarded by consumers? Examine with a two-tail, alpha =. 01 test out. Do NOT execute a confidence time period. Answer H0: There not any significant gender wise difference in the portion customers who preferred the merchandise.

H1: Presently there significant male or female wise big difference in the amount customers who preferred the merchandise. P? P2 n p? n s 1 The test Statistic utilized is Unces test Unces? where p= 1 one particular 2 2 n1? n2? 1 1? P(1? P)?? n1 n2? Decision rule: Reject the null hypothesis, if the determined value of test figure is higher than the critical value. Details Z Evaluation for Variations in Two Amounts Data Hypothesized Difference Degree of Significance Group 1 Quantity of Successes Sample Size Group 2 Volume of Successes Test Size zero 0. 01 Male 120 300 Female 92 70 Intermediate Calculations Group 1 Proportion 0. 4 Group 2 Amount 0. 328571429 Difference in Two Dimensions 0. 071428571 Average Amount 0. 365517241 Z Test out Statistic 1 . 784981685 Two-Tail Test Lower Critical Worth -2. 575829304 Upper Crucial Value 2 . 575829304 p-Value 0. 074264288 Do not deny the null hypothesis Realization: Fails to decline the null hypothesis. The sample would not provide enough evidence to support the claim that there significant gender wise difference inside the proportion clients who recommended the product. 5

PROBLEM 5 Assuming that the people variances will be equal for Male and feminine GPA’s, test out the following test data to see if Male and feminine PhD candidate GPA’s (Means) are equal. Conduct a two-tail hypothesis test for? =. 01 to determine perhaps the sample means are different. Will not do a confidence interval. Men GPA’s Woman GPA’s Sample Size 12 13 Test Mean installment payments on your 8 4. 95 Test Standard Dev. 25. eight Answer H0: There is no factor in the indicate GPA of males and Females H1: There is significant difference in the indicate GPA of males and Females. Evaluation Statistic utilized is independent sample capital t test.? X1? X 2 S two (n1? 1) S12? (n2? 1) S2 n1n2 ~ tn1? n1? 2 wherever S? n1? n2? a couple of n1? n2 Decision guideline: Reject the null hypotheses, if the determined value of test figure is higher than the critical value. Particulars t Evaluation for Differences in Two Means Data Hypothesized Difference Degree of Significance Human population 1 Test Sample Size Sample Imply Sample Normal Deviation Populace 2 Test Sample Size Sample Mean Sample Normal Deviation More advanced Calculations Inhabitants 1 Test Degrees of Freedom Population a couple of Sample Examples of Freedom Total Degrees of Flexibility Pooled Variance 0. 05 12 2 . 8 0. 25 13 4. 96 0. eight 11 doze 23 zero. 363804 5 Difference in Sample Means t Test out Statistic -2. 15 -8. 90424 Two-Tail Test Decrease Critical Worth Upper Essential Value p-Value Reject the null hypothesis -2. 80734 2 . 807336 0. 0000 Conclusion: Decline the null hypotheses. The sample provides enough proof to support the claim that there is significant difference in the mean GP A score among the list of males and females. 6 PART II REGRESSION RESEARCH Problem a few You wish to work the regression model (less Intercept and coefficients) shown below: HAVE YOUR VOTE = CITY + PROFITS + TEACH

Given the Excel spreadsheet below pertaining to annual data from1970 to 2006 (with the data to get row 5 thru line 35 not really shown), full all necessary entries inside the Excel Regression Window shown below the info. 1 two 3 four A YEAR 70 1971 72 B ELECTION C CITY D INCOME E TEACH 49. zero 58. three or more 45. two 62. 0 65. 2 75. zero 7488 7635 7879 some. 3 almost eight. 3 5. 5 36 37 32 2004 2005 2006 50. 1 ninety two. 1 94. 0 96. 6 15321 15643 16001 4. 9 4. 7 5. you 67. six 54. a couple of Regression Input OK Input Y Range: A1: A38 Input Back button Range: B1: E38 End Help? Product labels Confidence Level: back button X By Output alternatives X Regular is Absolutely no 95 % Output Selection: New Worksheet Ply:

Fresh W orkbook Residuals Residuals Residual Plots Standardized Commissions Line In shape Plots Typical Probabilit y Normal Possibility Plots six PROBLEM six. Use the pursuing regression outcome to determine the pursuing: A real estate investor has devised a model to estimate residence prices in a new suburban development. Data for a randomly sample of 100 homes were accumulated on the selling price of the home (\$ thousands), your home size (square feet), the lot size (thousands of square feet), and the number of bedrooms. The next multiple regression output was generated: Regression Statistics Multiple R zero. 8647 3rd there’s r Square. 7222 Adjusted L Square zero. 6888 Standard Error 16. 0389 Observations 100 Intercept X1 (Square Feet) X2 (Lot Size) X3 (Bedrooms) Coefficients -24. 888 0. 2323 10. 2589 15. 2356 Standard Error 37. 3735 zero. 0184 1 . 7120 six. 8905 to Stat -0. 7021 9. 3122 5. 3256 several. 2158 P-value 0. 2154 0. 0000 0. 0001 0. 1589 a. Why is the pourcentage for BEDROOMS a positive number? The selling price increase if the number of areas increases. Thus the relationship is usually positive. b. Which is one of the most statistically significant variable? What evidence reveals this? Most statistically significant variable is definitely one with least g value.